7.2 Kinetic Energy - University Physics Volume 1 | OpenStax
https://openstax.org/books/university-physics-volume-1/pages/7-2-kinetic-energy
WebThen multiply by the number of molecules to get the total result. Finally, in part (c), we can substitute the amount of kinetic energy in part (b), and the mass of the basketball in part (a), into the definition K = 1 2 m v 2 K = 1 2 m v 2, and solve for v. Solution. The horizontal speed is (15 m)/(2 s), so the horizontal kinetic energy of the ...
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